if <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
![if ltABC measures 100 and is inscribed in a circle O find ltBAO and ltBCO class=](https://us-static.z-dn.net/files/d12/ade1e019c758f25ba472e0f101dc56e2.jpg)
Answer:
<BCO = <BAO = 20degrees
Step-by-step explanation:
If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
To get <BAO and <BCO, we need to get <AOC first.
From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;
<BAC + <BCA + 100 = 180
Since <BAC = <BCA
<BAC + <BAC = 180 - 100
2<BAC = 80
<BAC = 80/2
<BAC = 40
Also;
<BAO = <BCO and <BAO = <BAC/2
<BAO = 40/2 = <BCO
Hence <BCO = <BAO = 20degrees