Question

In the diagram, q1 = +2.00 x 10-5 C,
q2 = +3.80 x 10-6 C, and q3 = +5.30 x 10-5 C.
What is the electric potential energy, Ue, for
charge qy? Include the correct sign (+ or -).

Answer 1

Answer:

     U = 3.59 10⁻⁹ J

Explanation:

Electric potential energy is

             U = k ∑ $\frac{q_iq_j }{r_i_j}$

in this case

            U = k (q₁q₂ / r₁₂ + q₁q₃ / r₁₃ + q₂q₃ / r₂₃)

the distances are

            r₁₂ = 1.15

            r₁₃ = 1.15 +2.88 = 4.03 m

            r₂₃23 = 2.88

we substitute

            U = 9 109 (2 10-5 3.8 10-6 / 1.15 + 2 10-5 5.30 10-5 / 4.03 + 3.8010-6 53 010-5 / 2.88)

             U = 9 109 (6.609 10-11 + 2.63 10-10 + 6.99 10-11)

            U = 9 109 (39,899 10-11)

            U = 3.59 10⁻⁹ J

Answer 2

Answer:

Q2 = 0.0346 J

Explanation:

I don't know what Q1 is but I did solve for Q2. I'm using this because no other question has been asked to solve for Q2 :)