Question

Calculate surface tension of an enlarged radius of 4cm to 6cm and amount of work necessary for enlargement was 1.5×10^-4 joules

Answer 1

Answer:

$T=7.5*10^{-5}$

Explanation:

From the question we are told that:

Radius $r=2cm$

Work done $W=1.5×10^-4 joules$

Generally the equation for Work done is mathematically given by

 $W=T.dA$

Therefore

 $T=\frac{W}{dr}$

 $T=\frac{1.5*10^{-4}}{2}$

 $T=7.5*10^{-5}$