Find the area of each figure

Answer:
92
Step-by-step explanation:
this figure can be "split" into 3 sub-figures.
one rectangle in the middle, one triangle to the right, and one triangle on top.
these areas we can calculate very easily. and then we simply sum up all 3 of them and we have the answer.
it is clear, the area of a rectangle is length×width.
and the area of triangle is baseline×height/2.
where in a right-angled triangle one of the sides next to the 90 degree angle is the baseline and the other is the height.
the rectangle
R = 10×6 = 60
the triangle to the right
T1 = (14-10)×6/2 = 12
the triangle on the top
T2 = 10×(10-6)/2 = 20
so, the total area is
60+12+20 = 92
The area of the given figure is 92.
This figure contained 3 sub-figures.
One rectangle in the middle, one triangle to the right, and one triangle on top.
The area of these areas we can calculate very easily. and then we ad all 3 of them and we have the answer.
The area of a rectangle is,
[tex]A=length\times width.[/tex]
The area of triangle is
[tex]A^*= \frac{1}{2} \times base\times height[/tex]
Where in a right-angled triangle one of the sides next to the 90 degree angle is the baseline and the other is the height.
The area of rectangle
[tex]R =l\times w \\R=10\times 6 \\R= 60[/tex]
The triangle to the right
[tex]T_1 = (14-10)\times 6/2 = 12[/tex]
The triangle on the top
[tex]T_2 = 10\times (10-6)/2 = 20[/tex]
Therefore, the total area is,
60+12+20 = 92
Therefore the area of the given figure is 92.
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