Question

A jar contains 7 poker chips: 3 blue, 3 red and 1 white. You randomly select two chips from the jar. What is the probability that your selection includes two blue chips? Round your answer to two decimal places.

Answer 1

Answer:

ok so

7+3+3+1=14

and if you pull one out the chance is

3/14

then

2/13

so 3/14*2/13

0.03296703296

so the answer is

0.03

Hope This Helps!!!

Answer 2

Given :

A jar contains 7 poker chips: 3 blue, 3 red and 1 white.

Total poker chips =7

You randomly select two chips from the jar

Given the selection includes to blue chips

Lets find the the probability of selecting first blue chip

Probability = number of times event occur / total number of outcomes

Here we have 3 blue chips

so there is possible to blue chip occurring 3 times

Probability (selecting blue chip first time )=$\frac{3}{7}$

After selecting 1 blue chip , we are left with 2 more blue chips and total of 6 chips

Probability (selecting blue chip second  time )=$\frac{2}{6}=\frac{1}{3}$

Probability (selecting 2 blue chips)=$\frac{3}{7} \cdot \frac{1}{3} =\frac{1}{7}=0.14$

The probability that your selection includes two blue chips is 0.14

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