Question

A jar contains 7 poker chips: 3 blue, 3 red and 1 white. You randomly select two chips from the jar. What is the probability that your selection includes the white chip? Round your answer to two decimal places.

Answer 1

Answer:

The probability that you will have a white chip is 0.309

Step-by-step explanation:

You on the first try have a 1/7 or 14.285% chance the second one has a 1/6 or a 16.666% you then add them together and you have a 30.9% chance

Answer 2

The Probability of selecting white chips is $0.0286$.

Let,

• Number of blue chips $=3$

• Number of red chips $=3$

• Number of white chips $=1$

• Number of chips drawn $=2$

• Total chips $=7$

The probability of the poker chips is,

            $\ n(A)=3\\\\n(B)=3\\\\n(C)=1$

Lets find the the probability of selecting white clip:

"Probability $=$ Number  of outcomes/ Total outcomes"

Randomly select two chips from the jar,

• The probability of the first chip taken being white is,

           

                            $P(C)=\frac{n(c)}{n(s)} \\\\P(C)=\frac{1}{7}$

          If the first chip is not white then the probability of the second chip being white is,

                     $P(no\ white)=\frac{1}{6}$

• Since, (of the 6/7 times that the first was not white) is,

                            $\frac{1}{6} * \frac{1}{7} = \frac{1}{7}$

Total probability is the sum of the two probability is,

                            $P=\frac{1}{7} +\frac{1}{7} \\\\P=\frac{2}{7}=0.286$

Hence,

The Probability of selecting white chips is $0.0286$.

For more information:

               

https://brainly.com/question/24164645