Respuesta :

s1m1

Answer:

-x^4, and (2√x)/x

Step-by-step explanation:

4. [tex]- \sqrt{ x^{8} } = - \sqrt{x^{4} *x^{4} } = -x^{4}[/tex]

x^8 = x*x*x*x*x*x*x*x = (x*x*x*x)(x*x*x*x) = (x^4)(x^4)

5.

[tex]\sqrt{\frac{4}{x} } = \frac{\sqrt{4} }{\sqrt{x} } = \frac{2}{\sqrt{x} } \\\\\\\frac{2}{\sqrt{x} } * \frac{\sqrt{x} }{\sqrt{x} } = \frac{2\sqrt{x} }{x}[/tex]

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