How many solutions exist for the given equation 3x+13=3(x+6)+1 zero one two infinity many

Answer:
Zero
Step-by-step explanation:
Given: 3x+13=3(x+6)+1
Step 1: Expand
3x+13=3x+19
Step 2: Subtract 3 from both sides
3x+13-13=3x+19-13
Step 3: Simplify
3x=3x+6
Step 4: Subtract 3x from both sides
3x-3x=3x-3x+6
Step 5: Simplify
0=6
NO REAL SOLUTIONS
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Answer:
zero
Step-by-step explanation:
3x + 13 = 3(x + 6) + 1
3x + 13 = 3x + 18 + 1
3x - 3x = 18 + 1 - 13
0 = 18 + 1 - 13
0 = 6
NO SOLUTION