Answer: Any x-values greater than 3
Explanation:
[tex]\frac{7}{6} +\frac{x}{2} < x-\frac{1}{3} \\\\\frac{7}{6} +\frac{1}{3}<x-\frac{x}{2}\\\\\frac{7}{6} +\frac{2}{6}< \frac{2x}{2}-\frac{x}{2}\\\\\frac{9}{6} <\frac{2x-x}{2}\\\\2*\frac{9}{6} <\frac{2x-x}{2}*2\\\\3<2x-x\\\\x>3[/tex]