Answer:
[tex]d_2=-8.32ft[/tex]
Step-by-step explanation:
From the question we are told that:
Height of first draw down [tex]h=30[/tex]
Pump Discharge [tex]Q=250gallons/day[/tex]
Well 1 depth [tex]d_1=10ft[/tex]
Transmissivity[tex]\=T 10.0 ft2/day[/tex]
Radius[tex]r=0.5[/tex]
Well 2 depth [tex]d_2=50ft[/tex]
Generally the Thiem's equation for Discharge is mathematically given by
[tex]Q=\frac{2\piT(h_2-h_1)}{ln(\frac{r_2}{r_1})}[/tex]
[tex]250=\frac{2*\pi 10 (10-d_2)}{ln(\frac{50}{0.5})}[/tex]
[tex]1151.293=2*\pi 10 (10-d_2)[/tex]
[tex]d_2=-8.32ft[/tex]