Answer:
[tex]a = 18x[/tex]
Step-by-step explanation:
Given
[tex]\frac{1}{2}(a + d) = 10x[/tex]
[tex]\frac{1}{2}(b + c) = 8x[/tex]
[tex]\frac{1}{3}(b + c+d) = 6x[/tex]
Required
The value of (a)
We have:
[tex]\frac{1}{2}(a + d) = 10x[/tex] --- multiply by 2
[tex]\frac{1}{2}(b + c) = 8x[/tex] --- multiply by 2
[tex]\frac{1}{3}(b + c+d) = 6x[/tex] --- multiply by 3
So, we have:
[tex]\frac{1}{2}(a + d) = 10x[/tex]
[tex]a + d = 20x[/tex]
[tex]\frac{1}{2}(b + c) = 8x[/tex]
[tex]b + c = 16x[/tex]
[tex]\frac{1}{3}(b + c+d) = 6x[/tex]
[tex]b + c + d= 18x[/tex]
Substitute [tex]b + c = 16x[/tex] in [tex]b + c + d= 18x[/tex]
[tex]16x + d = 18x[/tex]
Solve for d
[tex]d = 18x - 16x[/tex]
[tex]d = 2x[/tex]
Substitute [tex]d = 2x[/tex] in [tex]a + d = 20x[/tex]
[tex]a + 2x = 20x[/tex]
Solve for (a)
[tex]a = 20x - 2x[/tex]
[tex]a = 18x[/tex]