Question

Number of conducting plates of a multiplate capacitor is 5. The no. Of capacitors is
A.1
B.2
C.3
D.4
(Ans with explanation pls)

Answer 1

Answer:

4 capacitors

Explanation:

Given

$n = 5$ --- conducting plates

Required

The number of capacitor (c)

This is calculated as:

$c = n - 1$

So, we have:

$c = 5 - 1$

$c = 4$