Answer:
[tex]4 < c < 24[/tex]
Step-by-step explanation:
Given
[tex]a = 10[/tex]
[tex]b = 14[/tex]
Required
The possible length of c
Using triangle inequality theorem, we have:
[tex]a + b > c[/tex]
[tex]a + c > b[/tex]
[tex]b + c > a[/tex]
So, we have:
[tex]a + b > c[/tex]
[tex]10 + 14 > c[/tex]
[tex]24 > c[/tex]
Also:
[tex]a + c > b[/tex]
[tex]14 + c > 10[/tex]
[tex]c > 10 - 14[/tex]
[tex]c > - 4[/tex]
Lastly;
[tex]b + c > a[/tex]
[tex]10 + c > 14[/tex]
[tex]c > 14 - 10[/tex]
[tex]c > 4[/tex]
Write out all inequalities without negative consideration
[tex]24 > c[/tex]
[tex]c > 4[/tex]
Rewrite as:
[tex]c < 24[/tex] [tex]4 < c[/tex]
Writing both together, we have:
[tex]4 < c < 24[/tex]
Hence, the third side can take its value from the range: [tex]4 < c < 24[/tex]