Respuesta :
The mode of decay for each of the following unstable nuclides are (a) ⁵⁷Ti is beta decay (b) ⁵⁹Zn is Positron emission (c) ¹²³Ba is Positron emission (d) ⁶⁰Cr is beta decay.
How to determine the mode of decay ?
- Change in mass/atomic number: if A decrease by 4 and Z decrease by 2 then the mode of decay is alpha decay.
- Change in mass/atomic number: if A unchanged and Z increase by 1 then the mode of decay is beta decay.
- Change in mass/atomic number: if A unchanged and Z is also unchanged then the mode of decay is gamma decay.
- Change in mass/atomic number: if A unchanged and Z decrease by 1 then the mode of decay is Positron emission.
- Change in mass/atomic number: if A unchanged and Z decrease by 1 then the mode of decay is Electron capture.
Now lets predict the mode of decay for each of the following:
(a) Ti - 57
⁵⁷Ti₂₂ → ⁵⁷V₂₃ + ⁰e₋₁
Here A is unchanged and Z is increases by 1 so the mode of decay is beta decay.
(b) Zn - 59
⁵⁹Zn₃₀ → ⁵⁹Cu₂₉ + ⁰e₊₁
Here A is unchanged and Z is decreases by 1 so the mode of decay is Positron emission.
(c) Ba - 123
¹²³Ba₅₆ → ¹²³Cs₅₅ + ⁰e₊₁
Here A is unchanged and Z is decreases by 1 so the mode of decay is Positron emission.
(d) Cr -60
⁶⁰Cr₂₄ → ⁶⁰Mn₂₅ + ⁰e₋₁
Here A is unchanged and Z is increases by 1 so the mode of decay is beta decay.
Thus, from above conclusion we can say that (a) ⁵⁷Ti is beta decay (b) ⁵⁹Zn is Positron emission (c) ¹²³Ba is Positron emission (d) ⁶⁰Cr is beta decay.
Learn more about the Mode of decay here: https://brainly.com/question/2553049
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