Question

(08.04 MO) 8 A large diamond with a mass of 481.3 grams was recently discovered in a mine. If the density of the diamond is 3.51 cm, what is the volume? Round your answer to the nearest hundredth. (5 points) оа 48.23 cm Ob 55.91 cm3 ос 58.71 cm Od 137.1 cm3​

Answer 1

Answer:

Density is mass (in grams) per cc so the density is actually 3.51 gms / cc

density = 481.3 g / cc

volume (in cc) = 481.3 / 3.51

volume =  137.12 cc

Step-by-step explanation:

Answer 2

The volume of the considered diamond whose mass is 481.3 grams and density is 3.51 g/cm³ is given by: Option D: 137.1 cm³

How are density, volume and mass of a substance related?

Suppose that a finite amount of substance is there having its properties as:

• mass of substance = m kg
• density of substance = d kg/m³
• volume of that substance = v m³

Then, they are related as:

$d = \dfrac{m}{v}$

For this case, we're specified that:

• mass of the considered diamond= 481.3 g
• density of the diamond= 3.51 g/cm³
• volume of that diamond = v cm³ (assume)

Since the mass is in grams, and the density is in grams per cubic cm, so volume would be in cubic cm, after direct calculation.

Then, by the definition of density, we get;

$d = \dfrac{m}{v}\\\\v = \dfrac{m}{d} = \dfrac{481.3}{3.51} \approx 137.12 \approx 137.1\:\rm cm^3$

Thus, the volume of the considered diamond whose mass is 481.3 grams and density is 3.51 g/cm³ is given by: Option D: 137.1 cm³

Learn more about mass, volume and density relation here:

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