Question

What is the equation, in point-slope form, of the line that
is perpendicular to the given line and passes through the
point (-4,-3)?

Answer 1

Answer:

The equation of the line is $y + 3 = m(x + 4)$, in which m is found as such $am = -1$, considering a the slope of the given line.

Step-by-step explanation:

Equation of a line:

The equation of a line, in point-slope form, is given by:

$y - y_0 = m(x - x_0)$

In which m is the slope and the point is $(x_0,y_0)$

Perpendicular lines:

If two lines are perpendicular, the multiplication of their slopes is -1.

Passes through the point (-4,-3)

This means that $x_0 = -4, y_0 = -3$

So

$y - y_0 = m(x - x_0)$

$y - (-3) = m(x - (-4))$

$y + 3 = m(x + 4)$

The equation of the line is $y + 3 = m(x + 4)$, in which m is found as such $am = -1$, considering a the slope of the given line.