Respuesta :
Answer:
[tex]y=-8x+14[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
- A perpendicular bisector of a line segment is 1) perpendicular to the line segment and 2) passes through the midpoint of the line segment
- Perpendicular lines always have slopes that are negative reciprocals (ex. -2 and 1/2)
- Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of when x is 0)
1) Determine the midpoint of the line segment
Midpoint: [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex] where the coordinates of the endpoints are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the endpoints (-24, -54) and (40, -46)
[tex](\frac{-24+40}{2} ,\frac{-54+(-46)}{2} )\\(\frac{-24+40}{2} ,\frac{-54-46}{2} )\\(\frac{16}{2} ,\frac{-100}{2} )\\(8 ,-50)[/tex]
Therefore, the midpoint of line AB is (8,-50).
2) Determine the slope of the line segment
This will help us find the equation of the perpendicular bisector.
slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] where two given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the endpoints (-24, -54) and (40, -46)
[tex]= \frac{-46-(-54)}{40-(-24)}\\= \frac{-46+54}{40+24}\\= \frac{8}{64}\\= \frac{1}{8}[/tex]
Therefore, the slope of line AB is [tex]\frac{1}{8}[/tex].
3) Determine the slope of the perpendicular bisector
Because perpendicular lines always have slopes that are negative reciprocals, the slope of the perpendicular bisector is -8 (the negative reciprocal of 1/8). Plug this slope into [tex]y=mx+b[/tex]:
[tex]y=-8x+b[/tex]
4) Determine the y-intercept (b) of the perpendicular bisector
[tex]y=-8x+b[/tex]
Recall that we found the midpoint of line AB, (8,-50). The perpendicular bisector passes through this point. Plug (8,-50) into [tex]y=-8x+b[/tex] and solve for b:
[tex]-50=-8(8)+b\\-50=-64+b[/tex]
Add 64 to both sides to isolate b
[tex]-50+64=-64+b+64\\14=b[/tex]
Therefore, the y-intercept of the line is 14. Plug this back into [tex]y=-8x+b[/tex]:
[tex]y=-8x+14[/tex]
I hope this helps!