Question

Ahmad said that the volume of cone A is half the volume of cone B? Do you agree? Explain

Answer 1

Answer:

Yes, I agree

Step-by-step explanation:

See attachments for cone

Cone A

$h = 2r$

Cone B

R = 2r

$h=r$

The volume of a cone is

$V = \frac{1}{3}\pi r^2h$

For cone A, we have:

$V = \frac{1}{3}\pi r^2*2r$

$V_A = \frac{2}{3}\pi r^3$

For cone B, we have:

$V = \frac{1}{3}\pi *(2r)^2 * r$

$V = \frac{1}{3}\pi *4r^2 * r$

$V_B = \frac{4}{3}\pi r^3$

So, we have:

$V_B = 2 * \frac{2}{3}\pi r^3$

Substitute $V_A = \frac{2}{3}\pi r^3$

$V_B = 2 * V_A$

Make VA the subject

$V_A = \frac{1}{2}V_B$

Hence, I agree with Ahmad