Answer: [tex]\dfrac{15}{64}[/tex]
Step-by-step explanation:
Given
Inside radius of figure [tex]r_1=\frac{14}{2}=7\ ft[/tex]
Outside radius of figure [tex]r_2=\frac{16}{2}=8\ ft[/tex]
Area of outside region is [tex]A_1=\pi (8^2)[/tex]
Area of inside region [tex]A_2=\pi (7)^2[/tex]
Area of shaded region [tex]A_1-A_2[/tex]
Probability that point lies inside the shaded region is
[tex]\Rightarrow P=\dfrac{A_1-A_2}{A_1}\\\\\Rightarrow P=\dfrac{\pi (8^2-7^2)}{\pi 8^2}\\\\\Rightarrow P=\dfrac{64-49}{64}\\\\\Rightarrow P=\dfrac{15}{64}[/tex]
