Question

There is a bag filled with 5 blue and 6 red marbles.
Marble is taken at random from the bag, the colour is noted and then it is replaced.
Another marble is taken at random.
What is the probability of getting 2 reds?
thanks,

Answer 1

Answer:

$(\frac{6}{11} )*(\frac{6}{11} )$ = 36/121 =.297

Step-by-step explanation:

Answer 2

Answer:

36/121

Step-by-step explanation:

We have 5+6 = 11 marbles

P(red) = number of red/ total = 6/11

We replace the marble so we still have 11 marbles

P(red) = number of red/ total = 6/11

P(red, red) = 6/11*6/11 = 36/121