The continuation of the electronic configuration would be 3p6, 4s2, 3d4
The initial p-orbital (the 3p3) is incompletely filled. Thus, the first thing would be to fill it completely (3p6) so as to obey the orbital-filling rule. This leaves 6 more electrons
After 3p orbital, the next orbitals are 4s, 3d, 4p, 5s, etc.
The 4s orbital will take a maximum of 2 electrons, leaving 4 more electrons.
Next would be the 3d orbital which can take a maximum of 8 electrons, but only 4 electrons are left.
Thus, the electronic configuration would be 3p6, 4s2, 3d4.
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