Question

Find the surface area of a water tower that is 40 feet tall and 20 feet across the base.
______ square feet​

Answer 1

Answer:

the surface area is 3140 square feet

Step-by-step explanation:

The computation of the surface area is given below:

Given that

Diameter = 20 feet

radius =  20 ÷ 2 = 10 feet

Surface area =  

= 2 × 3.14 × (10)^2 + 2 × 3.14 × 10 × 40

= 6.28  × 100  + 6.28  × 400

= 628 + 25.12  × 100

= 628+ 2512

= 3140 square feet

hence, the surface area is 3140 square feet

Answer 2

The surface area is 3140 feet².

What is Surface Area?

Surface area is the amount of space covering the outside of a three-dimensional shape.

Given that:

Diameter = 20 feet

radius =  20 ÷ 2 = 10 feet

Now, Surface area  will be,

=2πr²+ 2πrh

= 2 × 3.14 × (10)² + 2 × 3.14 × 10 × 40

= 6.28  × 100  + 6.28  × 400

= 628 + 25.12  × 100

= 628+ 2512

= 3140 feet²

hence, the surface area is 3140 feet².

Learn more Surface Area here:

https://brainly.com/question/27753868

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