Question

A 45 foot ladder is set against the side of a house so that it reaches up 27 feet. If Nicole grabs the ladder at its base and pulls it 4 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 23 ft.) Round to the nearest tenth of a foot.

Answer 1

Mark Brainliest please.

Answer : The ladder will reach 20.6 feet.

Explanation:

Refer the image attached for explanation

Answer 2

The ladder will reach a height of 20.6 feet

The given parameters are:

• Length = 45-foot
• Height = 27 feet

Start by calculating how far (d) the ladder is, from the bottom of the house using the following Pythagoras theorem

$45^2 = 27^2 +d^2$

Collect like terms

$d^2= 45^2 -27^2$

$d^2= 1296$

Take square roots of both sides

$d= 36$

When the ladder is moved 4 feet farther, the new distance becomes

$d= 36+4$

$d= 40$

The new height (h) of the ladder is then calculated using the following Pythagoras theorem

$45^2=40^2 + h^2$

Collect like terms

$h^2 = 45^2-40^2$

$h^2 = 425$

Take the square roots of both sides

$h = 20.6$

Hence, the ladder will reach a height of 20.6 feet

Read more about Pythagoras theorem at:

https://brainly.com/question/654982