Following are the simplification to the given equation:
Given:
[tex]\to \frac{4x^2+ 4x}{2x^2-2}[/tex]
To find:
simplify=?
Solution:
Using formula:
[tex]\to (a^2-b^2)= (a+b)(a-b)[/tex]
[tex]\to \frac{4x^2+ 4x}{2x^2-2}[/tex]
In the numerator part common the value 4x and in the denominator we common the value 2 then:
[tex]\to \frac{4x^2+ 4x}{2x^2-2}= \frac{4x(x+ 1)}{2(x^2-1)}\\[/tex]
[tex]= \frac{4x(x+ 1)}{2(x^2-1^2)}\\\\= \frac{4x(x+ 1)}{2(x-1)(x+1)}\\\\= \frac{4x}{2(x-1)}\\\\= \frac{2x}{(x-1)}\\\\[/tex]
Therefore, the final answer is "[tex]\frac{2x}{(x-1)}\\\\[/tex]"
Learn more about the Simplify:
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