Question

There are several vehicles in a parking lot. Some of them are motorcycles
(with 2 wheels), and some are cars (with 4 wheels). There are 10 vehicles in
the lot, and there are 32 wheels. How many vehicles of each type are in the
lot?

Answer 1

Answer:

There are four motorcycles and six cars.

Step-by-step explanation:

Let m represent the number of motorcycles and c represent the number of cars.

Since there are ten vehicles in total, the sum of the number of motorcycles and the number of cars must total ten. Hence:

$m+c=10$

And since each motorcycle has two wheels and each car has four wheels and there are 32 wheels in total:

$2m+4c=32$

Solve the system of equations. First, we can divide the second equation by two:

$m+2c=16$

From the first equation, we can subtract c from both sides:

$m=10-c$

Substitute:

$(10-c)+2c=16$

Simplify:

$10+c=16$

Therefore:

$c=6$

There are six cars.

Using the modified equation:

$m=10-c$

Solve for m:

$m=10-(6)=4$

So, there are four motorcycles and six cars.