a) Write down the exact value of tan 60' b) Find the value of h in this triangle, h= c) Write down the exact area of this triangle, h 60° 43
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Step-by-step explanation:
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a) The exact value of tan 60 degree is [tex]\sqrt{3}[/tex].
b) The value of h in the given triangle is √3.
c) The area of the given triangle is 24[tex]\sqrt{3}[/tex].
The tangent of an angle is the ratio of the length of the opposite side to the length of the adjacent side.
The value of tan 60 degree is [tex]\sqrt{3}[/tex].
[tex]Area = \frac{1}{2}bh[/tex]
Where,
b is the base of the triangle.
h is the height of the triangle.
a) Since, the value of tan60 degree is [tex]\sqrt{3}[/tex].
Hence, the exact value of tan 60 degree is [tex]\sqrt{3}[/tex].
b). According to the given question, we have a right angled triangle in which
The length of the adjacent side w.r.t angle 60 degrees is [tex]4\sqrt{3}[/tex].
And, the length of the opposite side w.r.t angle 60 degrees is h.
Therefore, the value of h in the given triangle is given by
[tex]tan60 = \frac{h}{4\sqrt{3} }[/tex]
⇒[tex]\sqrt{3} =\frac{h}{4\sqrt{3} }[/tex] (because tan60=√3)
⇒[tex]h=4\sqrt{3} \sqrt{3}[/tex]
⇒[tex]h = 12[/tex]
Hence, the value of h in the given triangle is √3.
c) For the given triangle
Length of base = 4[tex]\sqrt{3}[/tex] unit.
And, the height of the given triangle is 12 unit.
The area of the given triangle is given by
[tex]Area = \frac{1}{2} (4\sqrt{3} )(12)[/tex]
⇒[tex]Area =24\sqrt{3}[/tex]
Hence, the area of the given triangle is 24[tex]\sqrt{3}[/tex].
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