9514 1404 393
Answer:
Step-by-step explanation:
For "mixture" problems, I like to let the variable represent the amount of the largest contributor. Here, we can let x represent the amount invested at 5%. Then the amount invested at 1% is (7000-x). The total interest earned is ...
0.05x +0.01(7000 -x) = 202
0.04x = 132 . . . . . . . . simplify, subtract 70
x = 3300
(7000 -x) = 7000 -3300 = 3700 . . . . at 1%
$3700 was invested at 1% interest.
$3300 was invested at 5% interest.