Question

simultaneous equation -- 4x+3y=16 .. 5x-y=1

Answer 1

Answer:

(1, 4)

Step-by-step explanation:

4x + 3y = 16

5x - y = 1

20x + 15y = 80            (Subtract the equations)

20x - 4y = 4

                          

19y = 76

y = 4

Substitute into any of the original equations:

4x + 3(4) = 16

4x + 12 = 16

4x = 2

x = 1

x = 1, y = 4

Answer 2

Answer:

x = 1 and y = 4

Step-by-step explanation:

4x + 3y = 16

5x - y = 1

→ Rearrange the second equation to make y the subject

y = 5x - 1

→ Substitute this into the first equation

4x + 3 ( 5x - 1 ) = 16

→ Expand

4x + 15x - 3 = 16

→ Simplify

19x - 3 = 16

→ Add 3 to both sides

19x = 19

x = 1

→ Substitute this solution into 5x - y = 1

( 5 × 1 ) - y = 1

→ Simplify

5 - y = 1

→ Minus 5 from both sides

-y = -4

→ Multiply both sides by -1

y = 4