Question

show the solution 3×(2÷3)^3+(2÷3)^2−20×2÷3+12​

Answer 1

Answer with Step-by-step explanation:

We are given that

$3\times (2\div 3)^2+(2\div 3)^2-20\times 2\div 3+12$

$3\times (\frac{2}{3})^3+(\frac{2}{3})^2-20\times \frac{2}{3}+12$

$3\times \frac{8}{27}+\frac{4}{9}-\frac{40}{3}+12$

$\frac{24}{27}+\frac{4}{9}-\frac{40}{3}+12$

$\frac{24+12}{27}-\frac{40}{3}+12$

$\frac{36}{27}-\frac{40}{3}+12$

$\frac{4}{3}-\frac{40}{3}+12$

$\frac{4-40}{3}+12$

$-\frac{36}{3}+12$

$-12+12$

$=0$