[tex]\huge\bold{Given :}[/tex]
Angle ABC = 81°
Angle BAC = a°
Angle BCA = 62°
[tex]\huge\bold{To\:find :}[/tex]
The measure of a.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]
[tex]\longrightarrow{\green{a.\:37°}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
We know that,
[tex]\sf\pink{Sum\:of\:angles\:of\:a\:triangle\:=\:180°}[/tex]
➪ ∠ ABC + ∠ BAC + ∠ BCA = 180°
➪ 81° + a° + 62° = 180°
➪ a° + 143° = 180°
➪ a° = 180° - 143°
➪ a° = 37°
Therefore, the measure of a is 37°.
Now, the three angles of the triangle are 81°, 37° and 62°.
[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]
∠ ABC + ∠ BAC + ∠ BCA = 180°
✒ 81° + 37° + 62° = 180°
✒ 180° = 180°
✒ L. H. S. = R. H. S.
[tex]\boxed{Hence\:verified.}[/tex]
( Note: Kindly refer to the attached file. )
[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{ヅ}}}}}[/tex]
