Question

Please solve with explanation

Answer 1

Answer:

56+8√2=8(7+√2)

Step-by-step explanation:

1. P= AB+BC+CD+DE+EF+FG+GA

2. AB=DC=12

BC=16

AG=ED=4

AG+ED+GE=16

4+4+GE=16

GE=16-8

GE=8

GF²= EF²+GE²

GF²=64+64

GF²=128

GF=8√2

3.P= 12+16+12+4+8+8√2+4= 56+8√2

Answer 2

Answer:

Area = 160 sq cm

Perimeter = 67.31 cm

Step-by-step explanation:

Area of the figure = Area of rectangle with dimensions 16 cm and 12 cm - Area of the right triangle with base and height ecah 8 cm.

=16*12 - 1/2 * 8 *8

= 192 - 32

= 160 sq cm

GEF is a right triangle.

Therefore, by Pythagoras theorem:

$FG^2 = FE^2 + GE^2$

$\therefore FG^2 = 8^2 + 8^2$

$\therefore FG^2 = 64+64$

$\therefore FG^2 = 128$

$\therefore FG =\sqrt {128}$

$\therefore FG =11.3137085$

$\therefore FG = 11.31\: cm$

Perimeter of the figure

= 12 + 16 + 12+4+8+11.31+4

= 67.31 cm