Question

4 tan 45°+(2 sin 45°)(6 kos 45°)​

Answer 1

Answer: The final value is 10

Step-by-step explanation:

We are given:

$4\tan 45^o+(2\sin 45^o)(6\cos 45^o)$

We know that:

$\tan 45^o=1\\\sin 45^o=\frac{1}{\sqrt{2}}\\\cos 45^o=\frac{1}{\sqrt{2}}$

Putting values in the given equation, we get:

$\Rightarrow (4\times 1)+(2\times \frac{1}{\sqrt{2}})\times (6\times \frac{1}{\sqrt{2}})\\\\\Rightarrow 4+(\frac{2\times 6}{2})\\\\\Rightarrow (4+6)\\\\\Rightarrow 10$

Hence, the final value is 10