Question

Find two consecutive whole numbers that square root of 63 lies between

Answer 1

Given:

The number $\sqrt{63}$ lies between two whole numbers.

To find:

The two consecutive whole numbers.

Solution:

The perfect squares of natural numbers are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, ... .

The number 63 lies between 49 and 64.

$49<63<64$

Taking square root on each side, we get

$\sqrt{49}<\sqrt{63}<\sqrt{64}$

$7<\sqrt{63}<8$

Therefore, the number $\sqrt{63}$ lies between two whole numbers 7 and 8.