Question

The equation of the circle having center (5, 4) and touching y-axis is

A. x 2 + y2 – 10x – 8y + 25 = 0

B. x 2 + y2 – 5x + 4y + 8 = 0

C. x 2 + y2 – 5x + 4y + 8 = 0

D. x 2 + y2 – 42 – 5y + 10 = 0

Answer 1

Answer:

None Of the Above.

Step-by-step explanation:

As we know that the general equation of circle is

( x - h )^2 + ( y - k )^2 = r^2

putting h=5 and k= 4 and r= 5

x² + 25 - 10x + y² +16 - 8y = 25

x² + y² - 10x - 8y + 16 = 0 is the answer.

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