Answer:
[tex]x=\frac{33}{7}[/tex]
Step-by-step explanation:
Since ED is parallel to CA, the two triangles in the figure share all 3 angles and therefore must be similar. By definition, the corresponding sides of similar polygons are in a constant proportion.
Therefore, we have:
[tex]\frac{11}{11+x}=\frac{14}{20},\\14(11+x)=20\cdot 11,\\11+x=\frac{20\cdot 11}{14},\\x=\frac{110}{7}-11=\boxed{\frac{33}{7}}[/tex]
