Question

How do I do this trigonometry problem? or where do I even start.

Answer 1

Answer:

∅=6

Step-by-step explanation:

let ∅=x

$\csc(3x+15)=\frac{1}{\sin(3x+15)}\\\sin(5x+3)*(\frac{1}{\sin(3x+15)})\\\frac{\sin(5x+3)}{\sin(3x+15)}=1\\\sin(5x+3)=\sin(3x+15)\\5x+3=3x+15\\2x=12\\x=6$