Question

Which of the following are solutions to the quadratic equation? Check all that
apply.
x2 + 8x + 16 = 7

Answer 1

Answer:

x=-9/10

Step-by-step explanation:

2x+8x+16=7

Step 1: Simplify both sides of the equation.

2x+8x+16=7

(2x+8x)+(16)=7(Combine Like Terms)

10x+16=7

10x+16=7

Step 2: Subtract 16 from both sides.

10x+16−16=7−16

10x=−9

Step 3: Divide both sides by 10.

10x/10

=

−9/10

x=-9/10

Answer 2

Answer:

x = - 4 ± $\sqrt{7}$

Step-by-step explanation:

Given

x² + 8x + 16 = 7 ( subtract 16 from both sides )

x² + 8x = - 9

Using the method of completing the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(4)x + 16 = - 9 + 16

(x + 4)² = 7 ( take the square root of both sides )

x + 4 = ± $\sqrt{7}$ ( subtract 4 from both sides )

x = - 4 ± $\sqrt{7}$

Then

solutions are x = - 4 - $\sqrt{7}$ , x = - 4 + $\sqrt{7}$