Answer:
[tex]x-2y=-12[/tex]
Step-by-step explanation:
Hi there!
1) Determine the equation of the line in slope-intercept form
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)
Plug in the slope [tex]\frac{1}{2}[/tex]
[tex]y=\frac{1}{2}x+b[/tex]
Plug in the given point (6,9) and solve for b
[tex]9=\frac{1}{2}(6)+b\\9=3+b[/tex]
Subtract 3 from both sides
[tex]9-3=3+b-3\\6=b[/tex]
Plug 6 back into [tex]y=\frac{1}{2}x+b[/tex]
[tex]y=\frac{1}{2}x+6[/tex]
2) Rearrange the equation into standard form
Standard form: [tex]Ax+By=C[/tex] where A, B and C are integers and A is typically positive
[tex]y=\frac{1}{2}x+6[/tex]
Multiply both sides by 2 to remove the fraction
[tex]2y=1x+12\\2y=x+12[/tex]
Subtract x from both sides to isolate 12 as C
[tex]2y-x=x+12-x\\2y-x=12\\-x+2y=12[/tex]
Multiply both sides by -1 to make A positive
[tex]x-2y=-12[/tex]
I hope this helps!