Question

${( \frac{5}{3} )}^{2n + 1} {( \frac{5}{3} )}^{5} = ({ \frac{5}{3} )}^{n + 2}$
Pls include steps...
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Answer 1

Answer:

n = -4

Step-by-step explanation:

$(\frac{5}{3} )^2^n^+^1 * (\frac{5}{3} )^5 = (\frac{5}{3})^n^+^2$

in multiplication if the base are same u can add there exponent.

$(\frac{5}{3})^2^n^+^1^+^5 = (\frac{5}{3})^n^+^2$

base of both sides are equal so their exponent will be equal

2n + 1 + 5 = n + 2

2n + 6 = n + 2

2n - n = 2 - 6

n = -4