Respuesta :
Answer: In the given reactions neither reaction 1 nor 2 reaction leads to an increase in entropy.
Explanation:
The degree of randomness present in the molecules of a substance is called entropy.
In gases, molecules are held by weak forces due to which they move apart from each other. Hence, they have high entropy.
In liquids, molecules are a little close to each other so they have less entropy than gases.
In solids, molecules are tightly held together so they have least or negligible entropy.
As reaction 1 is [tex]CaO(s) + CO_{2}(g) \rightarrow CaCO_{3}(s)[/tex] and it shows that product is in solid state. Therefore, entropy is decreasing.
As reaction 2 is [tex]H_{2}O(g) \rightarrow H_{2}O(l)[/tex] and it shows that gas is converted into liquid. Therefore, entropy is also decreasing here.
Thus, we can conclude that in the given reactions neither reaction 1 nor 2 reaction leads to an increase in entropy.
