Question

The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 72 cm, what is the
length of the diagonal?
The length of the diagonal is
cm.
Give your answer to 2 decimal places.

Answer 1

Answer:

Step-by-step explanation:

W=2L-2

A=72

LW=72

L(2L-2) = 72

2L^2 -2L= 72

2L^2 -2L-72=0

L^2 - L -36 = 0

L= -5.52 or 6.52(neg # not a solution)

W=11.04

L=6.52

DIAG = $\sqrt{11.04^2+6.52^2}$ = 12.82

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