Question

Consider a 92.0 kg ice skater who is spinning on the ice. What is the moment of inertia of the skater, if the skater is approximated to be a solid cylinder that has a 0.140 m radius and is rotating about the center axis of the cylinder.

Answer 1

Answer:

$I=0.902kg*m^2$

Explanation:

From the question we are told that:

Mass $m=92.0kg$

Radius $r=0.140m$

Generally the equation for moment of Inertia is mathematically given by

 $I = 0.5*m*r^2$

 $I=0.5*(92)*0.14^2$

 $I=0.902kg*m^2$