cuanto me da como resultado
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Step-by-step explanation:
1) [tex](-4)^2{\cdot}(-4)[/tex]
We know that, [tex]a^x{\cdot}a^y=a^{x+y}[/tex]
[tex](-4)^2{\cdot}(-4)=(-4)^{2+1}\\\\=(-4)^3\\\\=64[/tex]
2) [tex](-2)^5{\cdot} (-2)^3[/tex]
Again using above property,
[tex](-2)^5{\cdot} (-2)^3=(-2)^8\\\\=256[/tex]
3) [tex]5^{-3}[/tex]
We know that,
[tex]a^{-x}=\dfrac{1}{a^x}[/tex]
So,
[tex]5^{-3}=\dfrac{1}{5^3}\\\\=\dfrac{1}{125}[/tex]
4) [tex]2.5^2=2.5\times 2.5\\\\=6.25[/tex]
Hence, this is the required solution.