Answer:
The mother must be heterozygous.
Explanation:
t=Tay-Sachs trait
T=Normal trait
Parent genotype combinations:
Tt x Tt
Possible genotypes:
| T | t
T | TT | Tt
t | Tt | tt
Since it is a recessive trait there must be 2 of the recessive alleles for the trait to show. This means neither of the parents can be totally normal(TT).
Since both parents are considered normal the both must be heterozygous to be able to produce an child with Tay-Sachs.