Answer: The mass of water produced is 27 g
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of pentane = 18 g
Molar mass of pentane = 72.15 g/mol
Plugging values in equation 1:
[tex]\text{Moles of pentane}=\frac{18g}{72.15g/mol}=0.250 mol[/tex]
The given chemical equation follows:
[tex]C_5H_{12}+8O_2\rightarrow 5CO_2+6H_2O[/tex]
By the stoichiometry of the reaction:
If 1 mole of pentane produces 6 moles of water
So, 0.250 moles of pentane will produce = [tex]\frac{6}{1}\times 0.250=1.5mol[/tex] of water
Molar mass of water = 18 g/mol
Plugging values in equation 1:
[tex]\text{Mass of water}=(1.5mol\times 18g/mol)=27g[/tex]
Hence, the mass of water produced is 27 g
