Respuesta :
The question is incomplete, the complete question is:
A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing parts.
[tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{r}^{q}\textrm{p}+3_0^1\textrm{n}[/tex]
Answer: The complete equation formed is [tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{54}^{140}\textrm{Xe}+3_0^1\textrm{n}[/tex]
Explanation:
The general representation of an isotope is given as:
[rex]_Z^A\textrm{X}[/tex]
where,
A is the mass number, Z is the atomic number and X is the symbol of the element
In a nuclear reaction, total atomic number and total mass number on either side of the reaction remains the same
For the given chemical reaction:
[tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{r}^{q}\textrm{p}+3_0^1\textrm{n}[/tex]
On the reactant side:
Total atomic number = [96 + 0] = 96
Total mass number = [245 + 1] = 246
On the product side:
Total atomic number = [42 + r + 0] = 42 + r
Total mass number = [103 + q + 3] = 106 + q
Calculating for 'r' and 'q', we get:
[tex]96= 42 + r\\\\r=96-42=54[/tex]
[tex]246 = 106+q\\\\q=246-106=140[/tex]
Thus, the missing isotope is [tex]_{54}^{140}\textrm{Xe}[/tex]
Hence, the complete equation formed is [tex]_{96}^{245}\textrm{Cm}+_0^1\textrm{n}\rightarrow _{42}^{103}\textrm{Mo}+_{54}^{140}\textrm{Xe}+3_0^1\textrm{n}[/tex]
