Question

A person of weighing 0.62 kN rides in an elevator that has an upward acceleration of 1 m/s2. What is the magnitude of the force of the elevator floor on the person, in newtons

Answer 1

Answer:

Force = 63.27 Newton

Explanation:

Given the following data;

Weight = 0.62 kN = 0.62 * 1000 = 620 N

Acceleration = 1 m/s²

To find the magnitude of the force of the elevator floor on the person;

First of all, we would determine the mass of the elevator;

Weight = mass * acceleration due to gravity

We know that acceleration due to gravity is equal to 9.8 m/s²

Substituting into the above formula, we have:

620 = mass * 9.8

Mass = 620/9.8

Mass = 63.27 kg

Next, we would determine the force by using the formula;

Force = mass * acceleration

Force = 63.27 * 1

Force = 63.27 Newton