Question

100 points and reward brainliest!
(28-b)xb=187
b = ?

Answer 1

Answer:

$b=11, b=17$

Step-by-step explanation:

To get rid of the parenthesis, distribute:

$b(28-b)=187,\\28b-b^2=187$

Move all terms to one side and factor:

$b^2-28b+187=0,\\(b-11)(b-17)=0,\\\begin{cases}b-11=0,b=\boxed{11}\\b-17=0,b=\boxed{17}\end{cases}$

Answer 2

Answer:

b = 11, 17

Step-by-step explanation:

=> (28 - b) × b = 187

=> 28b - b² = 187

• subtracting 187 from both sides

=> 28b - b² - 187 = 0

• dividing the equation by (-1) and rearranging

=> b² - 28b + 187 = 0

• breaking -28b into 2 variables such that the variable multiply to form 187b²

=> b² - 11b- 17b + 187 = 0

{as (-11b)×(-17b) = 187b² and (-11b)+ (-17b) = -28b }

=> b (b - 11) - 17(b - 11) = 0

=> (b- 11)(b - 17) = 0

• either

(b - 11) = 0

=> b = 11

• or

(b - 17) = 0

=> b = 17

therfore,

b = 11, 17