So there’s two cell phones the length on first is 8.4 inches the width on the first cell phone is 5.6 inches. On the second cell phone the length is 9.21 inches. The length and width of the two cell phones are proportional. What is the width, inches of the larger of the cell phone?

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Answer:

The width, in inches of the larger cell phone is 6.14 inches.

Step-by-step explanation:

To solve we must set up a ratio.

[tex]\frac{8.4}{5.6} = \frac{9.21}{y}[/tex]

After setting this ratio up, we can cross multiply to solve for y.

8.4(y) = 5.6(9.21)

8.4(y) = 51. 576

To get y alone we divide by 8.4 on both sides.

y = 6.14

The width, in inches of the larger cell phone is 6.14 inches.

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