An airplane took off at a constant angle of elevation. After the plane traveled for 25 miles, it reached an altitude of 5 miles. To the nearest tenth of a degree, what was the angle of elevation?
![An airplane took off at a constant angle of elevation After the plane traveled for 25 miles it reached an altitude of 5 miles To the nearest tenth of a degree w class=](https://us-static.z-dn.net/files/d42/35e4498c806a32d3d2e7e45f9e466609.png)
Answer:
11.5 degrees
Step-by-step explanation:
For future reference trianglecalculator.net is very helpful
The angle of elevation to the nearest tenth of a degree is 11.54°.
An angle of elevation is defined as the angle between the slant horizontal line of an eye and the object in relation to the baseline called the adjacent.
In trigonometry, the angle of elevation can be determined by using the sine rule.
[tex]\mathbf{sin \ \theta = \dfrac{opp}{hyp} }[/tex]
[tex]\mathbf{sin \ \theta = \dfrac{5}{25} }[/tex]
[tex]\mathbf{ \theta =sin^{-1} (0.2)}[/tex]
[tex]\mathbf{ \theta =11.54^0}[/tex]
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